**Problem 1**

*If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.*

*Find the sum of all the multiples of 3 or 5 below 1000.*

**Solution**

# Add all the natural numbers below one

# thousand that are multiples of 3 or 5.

# this is interesting

# I wasn’t sure how to create the arrays

# with a step so I just rejected the ones

# I didn’t want. For small numbers this

# should work fine

threes = (0…1000).reject { |i| i % 3 != 0 }

fives = (0…1000).reject { |i| i % 5 != 0 }

fifteens = (0…1000).reject { |i| i % 15 != 0 }

answer = 0

threes.each { |i| answer += i }

fives.each { |i| answer += i }

fifteens.each { |i| answer -= i }

puts answer

**Discussion**

Remember, Ruby is brand new to me. I wasn’t really sure how to create an array with a step so I used the “reject” feature. It felt pretty natural.

If you have questions, leave a comment or find me on Twitter (@azzlsoft) or email (rich@azzlsoft.com).

### Like this:

Like Loading...

*Related*

## Leave a Reply