Problem 1
If we list all the natural numbers below 10 that are multiples of 3 or 5, we get 3, 5, 6 and 9. The sum of these multiples is 23.
Find the sum of all the multiples of 3 or 5 below 1000.
Solution
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<title>Project Euler 001</title>
</head>
<body>
<script type="text/javascript">
//Add all the natural numbers below one
//thousand that are multiples of 3 or 5.
//this one is pretty similar to c#
answer = 0
for (three = 0; three < 1000; three += 3) { answer += three; }
for (five = 0; five < 1000; five += 5) { answer += five; }
for (fifteen = 0; fifteen < 1000; fifteen += 15)
{ answer -= fifteen; }
document.write("<b>" + answer + "</b>");
</script>
</body>
</html>
Discussion
Last solution of the week. Nothing too special here.
If you have questions, leave a comment or find me on Twitter (@azzlsoft) or email (rich@azzlsoft.com).
azzlsoft.com 
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